4y^2-19y+15=

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Solution for 4y^2-19y+15= equation:


Simplifying
4y2 + -19y + 15 = 0

Reorder the terms:
15 + -19y + 4y2 = 0

Solving
15 + -19y + 4y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + -1y)(15 + -4y) = 0

Subproblem 1

Set the factor '(1 + -1y)' equal to zero and attempt to solve: Simplifying 1 + -1y = 0 Solving 1 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1y = 0 + -1 -1y = 0 + -1 Combine like terms: 0 + -1 = -1 -1y = -1 Divide each side by '-1'. y = 1 Simplifying y = 1

Subproblem 2

Set the factor '(15 + -4y)' equal to zero and attempt to solve: Simplifying 15 + -4y = 0 Solving 15 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-15' to each side of the equation. 15 + -15 + -4y = 0 + -15 Combine like terms: 15 + -15 = 0 0 + -4y = 0 + -15 -4y = 0 + -15 Combine like terms: 0 + -15 = -15 -4y = -15 Divide each side by '-4'. y = 3.75 Simplifying y = 3.75

Solution

y = {1, 3.75}

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